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Post by Gooman on Feb 1, 2009 8:52:19 GMT -6
well, you arn't dividing by 0. your dividing by (A-B). there is a difference. also, if A=B, the A may be .9 repeating and B may be 1. that way, they are the equal to each other, but dividing wouldn't equal 0.
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Post by abizarro on Feb 1, 2009 16:48:32 GMT -6
for A to be 0.9(recurring) and b to be 1 you'd need to agree that .9(recurring) and 1 are the same number (as a=b) therefore a-b equals zero.
if you didnt get that i'll do it again: a-b (substitute b for a as you stated a=b) a-a (now for some proving) if a=9 9-9=0 if a=2 2-2=0 if a=1534879 1534879-1534879=0 point is if a=b then a is b so a minus b(or as) will always equal 0. two does equal one but it also equal any other number because zero multiplied by anything equals zero.
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